Mat 540-Assignment 1

Days-to-Repair When determining the routine of geezerhood needed to repair a copier, it is best to assume that the number of days is stochastic. It is best to buzz off this random, which is illustrated on the excel spreadsheet as r2. R2 result be number among 0 and 1. To teach this value a random number entrust be generated in excel. The number of days needed to repair the copier will be determine based on the cumulative outline below: 0.00 > r2 < 0.20, thus it will sign up 1 day; 0.20 > r2 < 0.65, then it will take 2 days; 0.65 > r2 < 0.90, then it will take 3 days; and 0.90 > r2 < 1.00, then it will take 4 days. Intervals between Breakdowns Intervals between disruptions be a probability dispersion. The variables will be random and range between 0 by dint of 6 weeks. As the time continues, the probability will increase. To determine this number a function of x will be used, as illustrated. F(x) = x/18, for 0 thru 6, where x equals the weeks between machine breakdowns F(x) = x2/36, for 0 thru 6, this is the distribution function that can be further simplified r1 = x2/36, to change set the equation equal to r1 x = 6 * SQRT (r1), last equation.

lose Revenue Jet Copies demonstrates a uniform probability distribution as it pertains to the number of copies sold per day. The average sale is between 2,000 through 8,000 copies a day, at $0.10 a copy. This number is denoted on the excel spreadsheet as r3 by generating a random number between 2,000 and 8,000. To calculate the total amount of business alienated on any given day, the following calculations utilized: Lost Revenue = repair time * r3 * 0.10 The total amount of anomic revenue is $20,166.30. This number is not totally accurate, but is an propinquity of lost. The amount will always change significantly because r1, r2, and r3 are numbers generated randomly. To modernize a close approximation the breakdown will have to consist of 365 to account for... If you want to get a full essay, order it on our website: Orderessay

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